Step 1:

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The equations are

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\"\"

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\"\"

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The cross product of two normal vectors is the direction vector for the line of intersection.

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The normal vectors of two planes are

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\"\"

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\"\".

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The cross product of two vectors is

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\"\"

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\"\"

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The direction vector of line of intersection is \"\".

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Step 2:

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Solve the eqn(1) and eqn(2).

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Multiply eqn(1) on each side by 3.

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\"\".

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Subtract \"\" from eqn(2).

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\"\"

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Substitute \"\" in eqn(1)

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\"\"

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\"\".

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There are no solutions for \"\" and \"\".

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So, take the point \"\" as \"\"

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\"\".

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The \"\" is lie on the line of intersection.

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The direction vector of line of intersection is \"\".

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The parametric plane equation is

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\"\"

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\"\"

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\"\"

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The parametric equation is \"\".

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Solution:

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The parametric equation is \"\".

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(b)

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The equations are

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\"\".

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\"\".

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The normal vectors of two planes are

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\"\"

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\"\".

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The angle between two planes is

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\"\"

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\"\"

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The angle between two planes is \"\".

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Solution:

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The angle between two planes is \"\".

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