Step 1 :
\A, B, and C are the points lying on the line .
Since the point A lies on the y - axis, Substitute in the line equation.
Thus, the point A is .
Step 2 :
\The line from to B is perpendicular to AC .
Means that, the line BD is is perpendicular to AC .
\Find the slope of the line AC .
\The line equation is .
Write the equation in slope - intercept form of line equation , where m is slope and b is the y - intercept.
.
Compare the equation with .
Slope is .
Since the slopes of the perpendicular lines are negative reciprocals, slope of the line AC is .
Step 3:
\Find the line BD.
\Point-slope form of line equation is , where m is the slope and
is the point lies on the line.
Substitute the point and
in above equation.
Step 4 :
\Point B is the intersection point of the lines AC and BD.
\Substitute in
.
If , then
.
Thus, the point B is .
Step 5 :
\Since AB = BC, point B is the mid point of AC.
\Let the points are ,
, and
.
Mid point .
Equate the x and y coordinates.
\Thus, the point C is
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