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Step 1 :  

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(a)

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The function \"\".

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Differentiate with respect to x.

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\"\"

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Determination of critical points :

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The function \"\" is undefined when \"\".

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Equate \"\" to zero:

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\"\"

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The critical points are \"\" and \"\".

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Step 2 :

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Consider test intervals as \"\" and \"\".

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Interval Test Value Sign of \"\"Conclusion
\"\" \"\" \

\"\"

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Increasing
\"\" \"\" \

\"\"

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Decreasing
\"\" \"\" \

\"\"

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Decreasing
\"\" \"\" \

\"\"

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Increasing
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Thus, The function is increasing on the intervals \"\" and \"\" .

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And The function is decreasing on the intervals \"\" and \"\".

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Solution :

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The function is increasing on the intervals \"\" and \"\" .

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The function is decreasing on the intervals \"\" and \"\".

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