(a)

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Step 1:

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The differential equation is \"\".

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The initial condition is \"\" and \"\"-value is \"\".

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Step size is \"\".

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Euler method is a numerical approach to approximate the  particular solution of the differential equation.

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Let \"\" that passes through the point \"\".

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From this starting point, one can proceed in the direction indicated by the  slope.

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Use a small step \"\", move along the tangent line.

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\"\" and \"\".

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Step 2:

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Use step size \"\", \"\", \"\" and \"\".

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\"\"

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\"\"

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So we have \"\", \"\", \"\", \"\",.....and,

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\"\"

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\"\"

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Step 3:

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Proceeding with similar calculations, we get the values in the table:

\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \
\"\"\"\"\"\"\"\"\"\"\"\"\"\"\"\"\"\"\"\"\"\"\"\"
\"\"\"\"\"\"\"\"\"\"\"\"\"\"\"\"\"\"\"\"\"\"\"\"
\"\"\"\"\"\"\"\"\"\"\"\"\"\"\"\"\"\"\"\"\"\"\"\"
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 From the table particular solution at x = 2 is 3.031.

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 Solution:

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The particular solution at x = 2 is 3.031.

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(b)

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Step 1:

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The differential equation is \"\".

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The initial condition is \"\".

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Solution to the differential equation :

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\"\"

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Integrate on each side.

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\"\"

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Substitute initial conditions \"\", \"\".

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\"\"

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The exact solution is \"\".

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 Solution:

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The exact solution is \"\".

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(c)

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Step 1:

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The differential equation is \"\".

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From Euler method, particular solution at x = 2 is 3.031.

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The exact solution is \"\".

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From the exact solution, the particular solution :

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Substitute x = 2 in exact solution.

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\"\"

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Solutions to the 3rd degree equation are \"\".

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Imaginary values are neglected.

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So the particular solution at x = 2 is 3.

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Therefore the particular solution is almost same in both methods.

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 Solution:

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The particular solution at x = 2 is 3.

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