(a)
\Step 1:
\The differential equation is .
The initial condition is and
-value is
.
Step size is .
Euler method is a numerical approach to approximate the particular solution of the differential equation.
\Let that passes through the point
.
From this starting point, one can proceed in the direction indicated by the slope.
\Use a small step , move along the tangent line.
and
.
Step 2:
\Use step size ,
,
and
.
So we have ,
,
,
,.....and,
Step 3:
\Proceeding with similar calculations, we get the values in the table:
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From the table particular solution at x = 2 is 3.031.
\Solution:
\The particular solution at x = 2 is 3.031.
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(b)
\Step 1:
\The differential equation is .
The initial condition is .
Solution to the differential equation :
\Integrate on each side.
\Substitute initial conditions ,
.
The exact solution is .
Solution:
\The exact solution is .
\
(c)
\Step 1:
\The differential equation is .
From Euler method, particular solution at x = 2 is 3.031.
\The exact solution is .
From the exact solution, the particular solution :
\Substitute x = 2 in exact solution.
\Solutions to the 3rd degree equation are .
Imaginary values are neglected.
\So the particular solution at x = 2 is 3.
\Therefore the particular solution is almost same in both methods.
\Solution:
\The particular solution at x = 2 is 3.
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