Step 1 :

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Freezing point of water \"\", where

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\"\" is the change in temperature and ,

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\"\" is the van t Hoff factor,

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\"\" is the molality of the solution and

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\"\" is the molality depression constant = \"\".

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Freezing point : \"\".

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\"\" for sodium chloride is 2.

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\"\"

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Substitute \"\" and \"\" in above equation.

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\"\".

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\"\"

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Freezing point of 1 molal aqueous sodium chloride solution is \"\".

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Step 2 :

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Freezing point : \"\".

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\"\" for glucose is 3.

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\"\"

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Substitute \"\" and \"\" in above equation.

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\"\".

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\"\"

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Freezing point of 1 molal aqueous glucose solution is \"\".

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Step 3 :

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Observe the above calculations.

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1 molal aqueous sodium chloride has the lower Freezing point compare with 1 molal aqueous glucose.

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Solution:

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1 molal aqueous sodium chloride has the lower Freezing point compare with 1 molal aqueous glucose.