Step 1:
\The molality of NaCl solution is 1.32 molal.
\ for
is 1.86
.
Freezing point is .
Where,
\ is the change in temperature.
is the molality depression constant.
m is the molality of NaCl solution.
\i is the von t Hoff factor.
\Here i =2 for NaCl, ( NaCl completely dissociates into two ion).
\Since 1 mole of NaCl gives two moles of ions (1 mole of and 1 mole of
).
Substitute all values in the freezing point.
\New freezing point of NaCl solution is .
Solution :
\The freezing point of NaCl solution is .