Step 1:

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The molality of NaCl solution is 1.32 molal.

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\"\" for \"\" is 1.86 \"\".

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Freezing point is .\"\"

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Where,

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\"\" is the change in temperature.

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\"\" is the molality depression constant.

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m is the molality of NaCl solution.

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i is the von t Hoff factor.

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Here i =2 for NaCl, ( NaCl completely dissociates into two ion).

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Since 1 mole of NaCl gives two moles of ions (1 mole of \"\" and 1 mole of \"\").

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Substitute all values in the freezing point.

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\"\"

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New freezing point of NaCl solution is \"\".

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Solution :

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The freezing point of NaCl solution is \"\".