Step 1:
\The equation is .
Construct a table for different values of x :
\S.No | \![]() | \
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1 | \![]() | \
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2 | \![]() | \
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3 | \![]() | \
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4 | \![]() | \
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4 | \![]() | \
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5 | \![]() | \
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Note : The equation does not exist at , so
is not considered in the above table.
Step 2:
\Graph:
\1. Draw a coordinate plane.
\2. Plot the points found in tables and draw a smooth curves through these points.
\Observe the graph :
\The equation has a maximum at .
The equation has minimum at .
Step 3:
\The maximum of the function :
\ has a relative or local maximum at x = c , if
for every x in open interval around x = c.
The minimum of the function :
\ has a relative or local minimum at x = c , if
for every x in open interval around
.
Therefore, from the above two definitions maximum is less than the minimum.
\Solution :
\The graph of the function :
\The equation has a maximum at .
The equation has minimum at .