Step 1:

The functions are $\"\"$ and $\"\"$ . \ \

Graph:

Graph the functions are $\"\"$ and $\"\"$ .

Shade the region bounded by the curves in the intersection part.

$\"\"$

Note: The region shaded in blue color is the required area of region.

Step 2:

Definite integral as area of the region:

If $\"image\"$ and $\"image\"$ are continuous and non-negative on the closed interval $\"image\"$ ,

then the area of the region bounded by the graphs of $\"image\"$ and $\"image\"$ and the vertical lines $\"image\"$ and $\"image\"$ is given by

$\"image\"$ .

Observe the graph:

Upper curve is $\"\"$ .

Lower Curve is $\"\"$ .

Region bounded between $\"\"$ and $\"\"$ .

So the vertical lines are $\"\"$ and $\"\"$ .

Area of the region is $\"\"$ .

$\"\"$

Area of the region is 4.5 sq-units.

Solution:

Graph the region of graph of $\"\"$ and $\"\"$ is

$\"\"$

Area of the region is 4.5 sq-units.