Step 1:
\The chemical equations is .
Rate of the reaction is related to the concentration as , where
is the rate of the reaction,
is the rate constant,
and
are molar concentration of the reactants and
are the order of the reactants.
Case I)
\,
and
.
Case II)
\,
and
.
Case III)
\,
and
.
Case IV)
\,
and
.
Case V)
\,
and
.
Step 2:
\Find the values of and
.
Divide equation (1) by equation (2)
\Apply logarithm on each side.
\Step 3:
\Divide equation (2) by equation (4)
\Apply logarithm on each side.
\Orders of the reactions are and
.
Negative order indicates that the concentration of that species inversely proportional to the rate of a reaction.
\Substitute and
in the rate of change formula.
Solution:
\Orders of the reactions are and
.
\
\
\
\
\
Step 1:
\Observe the table.
\Rate of the reaction is related to the concentration as , where
is the rate of the reaction,
is the rate constant,
and
are molar concentration of the reactants and
are the order of the reactants.
If the initial concentration of is doubled, the time taken to complete the reaction is halved.
The rate of reaction is also doubled.
\So the order of the reactant is
.
Similarly,
\If the initial concentration of is doubled, the time taken to complete the reaction is halved.
The rate of reaction is also doubled.
\So the order of the reactant is
.
Step 2:
\Substitute and
in the rate of change formula.
Rate of concentration is
.
Solution:
\Order of the reactants are and
.
Rate constant .