Step 1:

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The chemical equations is \"\".

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Rate of the reaction is related to the concentration as \"\", where \"\" is the rate of the reaction, \"\" is the rate constant, \"\" and \"\" are molar concentration of the reactants and \"\" are the order of the reactants.

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Case I)

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\"\", \"\" and \"\".

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\"\"

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Case II)

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\"\", \"\" and \"\".

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\"\"

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Case III)

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\"\", \"\" and \"\".

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\"\"

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Case IV)

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\"\", \"\" and \"\".

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\"\"

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Case V)

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\"\", \"\" and \"\".

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\"\"

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Step 2:

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Find the values of \"\" and \"\".

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Divide equation (1) by equation (2)

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\"\"

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Apply logarithm on each side.

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\"\"

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\"\"

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Step 3:

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Divide equation (2) by equation (4)

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\"\"

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Apply logarithm on each side.

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\"\"

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\"\"

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Orders of the reactions are \"\" and \"\".

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Negative order indicates that the concentration of that species inversely proportional to the rate of a reaction.

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Substitute \"\" and \"\" in the rate of change formula.

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\"\"

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\"\"

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Solution:

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Orders of the reactions are \"\" and \"\".

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Step 1:

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Observe the table.

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Rate of the reaction is related to the concentration as \"\", where \"\" is the rate of the reaction, \"\" is the rate constant, \"\" and \"\" are molar concentration of the reactants and \"\" are the order of the reactants.

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If the initial concentration of \"\" is doubled, the time taken to complete the reaction is halved.

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The rate of reaction is also doubled.

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So the order of the reactant \"\" is \"\".

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Similarly,

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If the initial concentration of \"\" is doubled, the time taken to complete the reaction is halved.

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The rate of reaction is also doubled.

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So the order of the reactant \"\" is \"\".

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Step 2:

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Substitute \"\" and \"\" in the rate of change formula.

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Rate of concentration is \"\"

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\"\".

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Solution:

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Order of the reactants are \"\" and \"\".

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Rate constant  \"\".

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