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Step 1:

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The emf of the battery \"image\" is 25V.

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The internal resistance of the battery is \"\".

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Two series circuits with branches of \"\" connected in parallel.

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Draw a circuit with above specifications :

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 \"\"

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 Step 2:

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Find the equivalent resistance :

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Resistors \"\" are in series.

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Let \"\" is equivalent resistance of \"\".

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\"\"

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Resistors \"\" are in series.

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Let \"\" is equivalent resistance of \"\".

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\"\"

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Let \"\" is equivalent resistance of \"\".

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\"\"

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\"\"

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Now \"\" is in series with the internal resistance of the battery.

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\"\"

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\"\"

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 Step 3:

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Find the current in the circuit :

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From ohms law : \"\".

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\"\"

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Substitute \"\" in above formula.

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\"\"

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 Step 4:

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Apply Kirchho ffs current law (KCL) at each node :

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\"\"

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Apply Kirchho ffs voltage law (KVL) to first loop :

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\"\"

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\"\"

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Substitute \"\" in equation (1).

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\"\"

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Step 5 :

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The potential difference \"\" across the external resistor \"\" is \"\".

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Substitute \"\" and \"\" in above equation.

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\"\"

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The potential difference \"\" across the external resistor \"\" is \"\".

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Substitute \"\" and \"\" in above equation.

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\"\"

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The potential difference \"\" across the external resistor \"\" is \"\".

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Substitute \"\" and \"\" in above equation.

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\"\"

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The potential difference \"\" across the external resistor \"\" is \"\".

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Substitute \"\" and \"\" in above equation.

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\"\"

\ Solution : \

The potential difference across resistor \"\" is \"\".

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The potential difference across resistor \"\" is \"\".

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The potential difference across resistor \"\" is \"\".

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The potential difference across resistor \"\" is \"\". 

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