Step 1:

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First chemical  reaction is

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2CO(g) + O2(g)  <====> 2CO2(g)                             Equation (1)

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The reaction take place at temperature 25°C and equilibrium constant \"\".

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Second chemical  reaction is

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CO2(g)  <====> CO(g) + 1/2 O2(g)                             Equation (2)

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The reaction take place at temperature 25°C and equilibrium constant \"\".

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Find equilibrium constant \"\" for second reaction :

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Reverse the first equation .

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\ \ 2CO2(g)  <====>  2CO(g) + O2(g)

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If an equation is reversed Kc is inverted : Kc2 = 1/Kc1 .

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Divide the coefficients of second equation by 2. \ \ CO2(g)  <====> CO(g) + 1/2 O2(g)        \ \ If the coefficients are divided by 2, then take the square root of Kc.

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Therefore the equilibrium constant \"\" for second reaction is

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\"\"

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Substitute equilibrium constant \"\" of first reaction.

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\"\"

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\ \ So the equilibrium constant is \"\". \ \ Option A is correct choice . \ \

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