Step 1:
\ \ \ \A survey had conducted with 420,095 cell phone users.
\it was found that 135 developed cancer of the brain or nervous system.
\Survey says that probability of a person having cancer is 0.000340.
\Find the mean.
\Here number of samples n = 420095.
\Probability of a person having cancer is p = 0.000340.
\Since it follows binomial distribution,
\Mean .
Where n is number of samples,
\p is probability of success.
\142.8323
\Step 2:
\Find the standard deviation.
\Standard deviation .
Where n is number of samples,
\p is probability of success,
\q is probability of failure.
\Probability of failure q = 1 - p.
\q = 1 - 0.000340
\q = 0.99966.
\\
(2)
\Step 1:
\CIA had analyze the frequencies of letters of the alphabet.
\They had examine the 2600 characters on o page.
\They found that the letter r is used at rate 6% .
\Find the mean.
\Here number of samples n = 2600.
\Probability of letter r is .
Since it follows binomial distribution,
\Mean .
Where n is number of samples,
\p is probability of success.
\Step 2:
\Find the standard deviation.
\Standard deviation .
Where n is number of samples,
\p is probability of success,
\q is probability of failure.
\Probability of failure q = 1 - p.
\q = 1 - 0.06
\q = 0.94.
\\
\
\
\
\
(3)
\Step 1:
\In Harris poll 370 adults are regret getting tattoos.
\Based on this poll 20% say that they were too young to get tattos.
\Find the mean.
\Here number of samples n = 370.
\Probability of adults who regret tattoos is .
Since it follows binomial distribution,
\Mean .
Where n is number of samples,
\p is probability of success.
\Step 2:
\Find the standard deviation.
\Standard deviation .
Where n is number of samples,
\p is probability of success,
\q is probability of failure.
\Probability of failure q = 1 - p.
\q = 1 - 0.2
\q = 0.8.
\