Step 1:
\Find the current through 11 resistor :
Super Position Theorem :
\Take 4V voltage source at a time and replace all other with short or internal resistance.
\Equivalent resistance :
\11 resistor is in parallel with 7
resistor.
Resistance RT is in series with 5 resistor.
Resistance RP is in parallel with 9 resistor.
Resistance RQ is in series with 3 resistor.
Step 2:
\Circuit current :
\Current across each resistor :
\.
Step 3:
\Now Short circuit the second voltage source.
\Take 8V voltage source at a time and replace all other with short or internal resistance.
\Equivalent resistance :
\3 resistor is in parallel with 9
resistor.
Resistance RT is in series with 5 resistor.
Resistance RP is in parallel with 11 resistor.
Resistance RQ is in series with 7 resistor.
Step 2:
\Circuit current :
\Current across each resistor :
\.
Step 5:
\Current through 11 resistor =
= Current produced by 11 resistor due to 8 V - Current produced by 11
resistor due to 4 V
(Since they are in opposite direction)
\= 0.649 - 0.132
\= 0.517
\Current through 11 resistor is 0.517 A.