Step 1:
\Find the current through 6 resistor :
Super Position Theorem :
\Take one voltage source at a time and replace all other with short or internal resistance.
\Indicate the direction of current in the above circuit.
\Equivalent resistance :
\9 resistor is in parallel with 6
resistor.
Resistance RT is in series with 7 resistor.
Step 2:
\Circuit current :
\Current across each resistor :
\Step 3:
\Now Short circuit the second voltage source.
\Indicate the direction of current in the above circuit.
\Equivalent resistance :
\7 resistor is in parallel with 6
resistor.
Resistance RT is in series with 9 resistor.
Step 4:
\Circuit current :
\Current across each resistor :
\Step 5:
\Current through 6 resistor =
= Current produced by 6 resistor due to 5 V + Current produced by 6
resistor due to 10 V
= 0.282 + 0.440
\= 0.722
\\