Step 1:

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(1.1.1)

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A resistance of \"\" is connected in parallel with \"\" resistor.

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If two resistors  \"\"  connected in parallel, then equivalent resistor is given by,

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\"\".

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Substitute \"\" and \"\" in the above formula.

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\"\"

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This  \"\"resistance comes in series with unknown resistor \"\" and circuit is connected to 10 V supply.

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If the two resistors \"\" are in series, then equivalent resistor is given by,

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\"\".

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Substitute \"\" and \"\" in the above formula.

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\"\".

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When a 2 A current is drawn from the supply of 10 V.

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From the ohms law: \"\".

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Substitute \"\" and \"\" in above formula.

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\"\"

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This resistance is equal to the equivalent resistance.

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\"\"

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Therefore value of the unknown resistor is \"\" when 2 A current is drawn from the source.

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Step 2:

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Power dissipated in the circuit:

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Power dissipated in the circuit with current drop \"\" and supply voltage \"\" is given by,

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\"\".

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Substitute \"\" and \"\" in the above formula.

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\"\"

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Power dissipated in the circuit is 20 watt.

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Solution:

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The value of the unknown resistor is \"\" when 2 A current is drawn from the source.

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Power dissipated in the circuit is 20 watt.

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