Step 1:
\Find the current through 8 resistor :
Super Position Theorem :
\Take one voltage source at a time and replace all other with short or internal resistance.
\Indicate the direction of current in the above circuit.
\Equivalent resistance :
\6 resistor is in parallel with 8
resistor.
Resistance RT is in series with 4 resistor.
Step 2:
\Circuit current :
\Current across each resistor :
\Step 3:
\Now Short circuit the second voltage source.
\Indicate the direction of current in the above circuit.
\Equivalent resistance :
\4 resistor is in parallel with 8
resistor.
Resistance RT is in series with 6 resistor.
Step 4:
\Circuit current :
\Current across each resistor :
\Step 5:
\Current through Load resistor 8 =
= Current produced by 8 resistor due to 5 V + Current produced by 100
resistor due to 7V
=0.2884+0.2692
\= 0.5576
\Current through 8 resistor is 0.5576 A.
Solution:
\Current through 8 resistor is 0.5576 A.