Step 1:

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Step 2:

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Find the current through the resistance R4.

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 Thevenins Theorem :

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Thevenins Theorem states that it is possible to simplify any linear circuit, no matter how complex, to an equivalent circuit with just a single voltage source and series resistance connected to a load.

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Now reduce the circuit to a equivalent Thevenins circuit .

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Find the Equivalent Resistance (Rs):

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Find the Thevenin resistance by removing all power sources in the original circuit (voltage sources shorted and current sources open) and calculating total resistance between the open connection points.

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6Ω Resistor in parallel with the 20Ω Resistor .

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Now the resistance \"\" in series with 5Ω Resistor .

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So thevenins resistance

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Find the Equivalent Voltage (Vs):

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Find the Thevenin source voltage by removing the load resistor from the original circuit and calculating voltage across the open connection points where the load resistor used to be.

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Apply KVL to the above circuit .

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 \"\" (The current in the second loop is zero since it is kept open )

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So the voltage drop across the 20 Ω resistor can be calculated as:

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Therefore the Thevenins Equivalent circuit is shown below with the 15 Ω resistor connected.

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The current across the load is

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