Step 1:

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The Length of the ladder is 8 m.

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Mass of the ladder m = 51.0 kg.

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Angle made by the ladder with respect to the ground is \"\".

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Mass of the fireman M = 81.6 kg.

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Distance travelled by the fireman is 4.80 m.

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Free body diagram of the data is

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\"\"

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Here FGx is the frictional force,  FGy is the Normal force and FW is the force exerted by the wall.

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Vertical Force :

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Sum of the forces in the vertical direction is equal to zero.

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\"\"

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Vertical Force \"\" N.

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Horizontal Force :

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Sum of the forces in the horizontal direction is equal to zero.

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\"\"     (Negative sign indicates opposite direction)      (1)

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To calculate Force exerted by the wall, consider sum of torque is zero.

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\"\"                                                 (2)

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Torque exerted by the wall along the ladder.

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Angle made by the ladder with respect to the wall is \"\".

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\"\"

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Torque exerted by the wall \"\" N-m.

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Torque exerted by the ladder:

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\"\"

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Torque exerted by the ladder \"\" N-m.

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Torque exerted by the person travelling along the ladder:

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\"\"

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Torque exerted by the person travelling along the ladder \"\" N-m.

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Substitute the values of the torque in equation (2).

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\"\"

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Force exerted by the wall is \"\" N.

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Substitute \"\" in equation (1).

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\"\"

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Horizontal force \"\" N.

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Solution:

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Horizontal force \"\" N.

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Vertical Force \"\" N.

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 Step 1:

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(b)

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Torque exerted by the ladder due to friction :

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\"\"

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Torque exerted by the ladder :

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\"\"

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Torque due to wall :

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\"\" .

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The clockwise torque balance the counterclockwise torque:

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\"\"

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Cancel the common terms.

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\"\"

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Coefficient of static friction is 0.6350.

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Solution:

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Coefficient of static friction is 0.6350.

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