Step 1:
\A DC generator has emf of 60 V.
\Internal resistance of the DC generator is 0.4 .
A battery has emf of 50 V.
\Internal resistance of the battery is 0.3 .
DC generator and battery are connected in parallel to the load of 10.6 .
Draw a circuit with above specifications.
\Step 2:
\Find the current through generator :
\Redraw the circuit with current directions and nodes.
\Apply Junction rule at node b.
\Apply KVL to a loop abeda.
\Apply KVL to a loop bcfeb.
\
Substitute equation (1) in equation (2) and (3).
\Solve the equations (4) and (5).
\Add the equations (4) and (5).
\Substitute in equation (4).
Substitute in
.
So the value of current through the generator is 17.2043 A.
\The direction of the current is toward the node b.
\Step 3:
\(b)
\The value of current through the battery is .
So the value of current through the battery is 12.968 A.
\The direction of the current is toward the node c. (In opposite direction with respect to generator)
\Step 4:
\Find the terminal voltage across the load.
\The current across the load is .
Use ohms law : .
Where i is current through load,
\R is resistance offered by load.
\The voltage across the load is 54.1395 V.
\Solution:
\(a)
\The value of current through the generator is 17.2043 A.
\The direction of the current is toward the node b.
\(b)
\The value of current through the battery is 12.968 A.
\The direction of the current is toward the node c.
\(c)
\The voltage across the load is 54.1395 V.
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