Step 1:
\The concentration of acetic acid is [HCH2H3O2] is 0.100 M.
\ka for acetic acid is .
The concentration of sodium hydroxide is [NaOH] is 0.100 M.
\The equation is
\ \ \
Equilibrium Constant : .
Relation between ka and kb : .
Step 1:
\ generates one mole of
and one mole of
.
Let then
.
\ \
Step 2:
\Find the pH of the solution.
\Definition of pOH: .
Now .
The pH of the solution is 8.872.
\Solution:
\The pH of the solution is 8.872.
\