Step 1:

\

\"\"

\

Find the current through 6\"\" resistor :

\

Super Position Theorem :

\

Take one voltage source at a time and replace all other with short or internal resistance.

\

\"\"

\

Indicate the direction of current in the above circuit.

\

Equivalent resistance :

\

9\"\" resistor is in parallel with 6\"\" resistor.

\

\"\"

\

Resistance RT is in series with 7\"\" resistor.

\

\"\"

\

Step 2:

\

Circuit current :

\

\"\"

\

Current across each resistor :

\

\"\"

\

\"\"

\

\"\"

\

Step 3:

\

Now Short circuit the second voltage source.

\

\"\"

\

Indicate the direction of current in the above circuit.

\

Equivalent resistance :

\

7\"\" resistor is in parallel with 6\"\" resistor.

\

\"\"

\

Resistance RT is in series with 9\"\" resistor.

\

\"\"

\

Step 4:

\

Circuit current :

\

\"\"

\

Current across each resistor :

\

\"\"

\

\"\"

\

\"\"

\

 Step 5:

\

Current through 6\"\" resistor =

\

             = Current produced by 6\"\" resistor due to 5 V + Current produced by 6\"\" resistor due to 10 V

\

             = 0.282 + 0.440

\

             = 0.722

\

 

\