Step 1:
\The standard deviation of the weights of certain machine components σ is 0.09 gr.
\Sample mean is µ = 8.3 gr.
\I am assuming that the mean the top and bottom is 3 %. \ \ so
\Z for 3 % confidence interval is and the top is 1.88. \ \
Let the values of the weights be x gr.
\x = µ + zσ
\The bottom number is .
Thus, x = 8.1308 lbs is the weight that separates the bottom 3 %.
\\
The top number is x = 8.3 + 1.88(0.09).
\
Thus, x = 8.4692 lbs is the weight that separates the top 3 %.
\Solution:
\The weight that separates the bottom 3 % is 8.1308 lbs.
\The weight that separates the top 3 % is 8.4692 lbs.
\