Step 1:
\The conviction rate of speeding is 85 %.
\Sample size n is 100.
\Probability of success p is 85% = 0.85.
\Probability of failure q is 1-0.85 = 0.15.
\Calculate mean.
\Mean .
.
Calculate standard deviation.
\Standard deviation .
.
Step 2:
\Find the probability that atleast there are 90 convictions .
Now calculate the Z-score for the given probability.
\,
where x is the conviction rate for speeding summons,
\ is the mean and
is the standard deviation.
For x = 90, Z-score with correction factor is .
From the Z-score table, Area of the region when Z = 1.260 is 0.8962.
\The probability of conviction rate for speeding summons greater than or equal to 90 is 0.0808.
\Note:
\Using TI-84 Calculator.
\Follow these steps to evaluate .
1.Select normalcdf()
\[2nd --> VARS --> 2 ]
\2.Enter the values of mean, standard deviation, limit.
\normalcdf(89.5, 9999, 85, 3.571)
\3.Now press Enter in calculator to view answer
\normalcdf(89.5, 9999, 85, 3.571)
\=0.01038
\Solution:
\The probability of conviction rate for speeding summons is 0.0808.
\\
\
\
\
\
\
Step 1:
\The probability that a radish seed will germinate is 0.7.
\Sample size n is 140.
\Find the probability of exactly 100 seeds will germinate .
Binomial Probability .
The probability of exactly 100 seeds will germinate is 0.06952.
\Check:
\Using TI-84 Calculator.
\Follow these steps to evaluate .
1.Select binomialpdf()
\[2nd --> VARS --> scroll down --> 0 ]
\2.Enter the values of sample size, probability and x.
\binomialpdf(140, 0.7, 100)
\3.Now press Enter in calculator to view answer
\binomialpdf(140, 0.7, 100)
\= 0.06952
\Solution:
\The probability of exactly 100 seeds will germinate is 0.06952.