1.(a)

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Step 1:

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The integrals are \"\" and \"\".

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The integral is \"\".

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Apply Additive interval property \"\".

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\"\"

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Substitute \"\" and \"\".

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\"\"

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\"\"

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\"\".

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Solution:

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\"\".

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1.(b)

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Step 1:

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The integrals are \"\" and \"\".

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The integral is \"\".

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Apply Additive interval property \"\".

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\"\"

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Substitute \"\" and \"\".

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\"\"

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\"\"

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\"\"

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\"\".

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Solution:

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\"\".

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1.(c)

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Step 1:

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The integrals are \"\" and \"\".

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The integral is \"\".

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Find \"\"

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Apply Additive interval property \"\".

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\"\"

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Substitute \"\" and \"\".

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\"\"

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\"\"

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\"\"

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\"\".

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\"\".

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Find

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Apply special definition of integrals:\"\".

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\"\".

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Substitute \"\" in \"\".

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\"\"

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\"\".

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\"\".

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Solution:

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\"\".

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1.(d)

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The integral is \"\".

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Area \"\"

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Apply properties of definite integrals:\"\".

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\"\" \ \

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\"\"

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\"\"

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\"\".

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Consider \"\".

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Substitute \"\".

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\"\"

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\"\"

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Back substitute \"\".

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\"\"

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\"\"

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\"\"

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\"\"

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\"\"

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\"\".

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\"\".

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Substitute \"\" in \"\".

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\"\".

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Solution:

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Area is \"\" square-units.

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