(11)
\Step 1:
\The function is and interval is
.
Absolute maxima or minima are exist either at the end points or at the critical numbers.
\Find the critical numbers :
\ is differentiable at all points because its a polynomial.
Therefore the solutions of are the only critical numbers.
Differentiate on each side with respect to t.
Equate to zero.
and
and
and
and
The critical number are ,
and
.
The end points are and
.
Step 2:
\Find the value of f at the critical numbers.
\Substitute in
.
.
Substitute in
.
.
Substitute in
.
.
Step 3:
\Find the value of f at the end points of the interval.
\Substitute in
.
\
.
Substitute in
.
\
.
Since the largest value is , absolute maximum is
.
Since the smallest value is , absolute minimum is
.
Solution :
\Absolute maximum is .
Absolute minimum is .
\
(12)
\Step 1:
\The function is and interval is
.
Absolute maxima or minima are exist either at the end points or at the critical numbers.
\Find the critical numbers :
\ is differentiable at all points because its a polynomial.
Therefore the solutions of are the only critical numbers.
Differentiate on each side with respect to x.
Equate to zero.
The critical number are .
The end points are and
.
Step 2:
\Find the value of h at the critical numbers.
\Substitute in
.
.
Find the value of h at the end points of the interval.
\Substitute in
.
\
\
.
Substitute in
.
\
.
Since the largest value is , absolute maximum is
.
Since the smallest value is , absolute minimum is
.
Solution :
\Absolute maximum is .
Absolute minimum is .