A common base amplifier produces an output current change of 4 mA with an input current of 2 µA. The output voltage changes with 6 V by means of 2 V input voltage.
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Calculate the following:
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4.3.1 hib
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4.3.2 hrb
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Step 1:
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The input current is 2 µA.
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The output current is 4 mA.
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The input voltage is 2 V.
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The output voltage is 6 V.
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Find ou
![\"\"](\"/test/fckeditor/editor/plugins/fckeditor_wiris/integration/showimage.php?formula=47f0f8830be4302fef67e20dc9c7d03b.png\")
and
![\"\"](\"/test/fckeditor/editor/plugins/fckeditor_wiris/integration/showimage.php?formula=295ae13927bdbfeca06b5bca3bddb9e7.png\")
in common base configuration.
Draw the common base configuration.
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Observe the figure.
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Input current is
![\"\"](\"/test/fckeditor/editor/plugins/fckeditor_wiris/integration/showimage.php?formula=b9398fc03997f912f925f69742c7c164.png\")
.
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Output current is
![\"\"](\"/test/fckeditor/editor/plugins/fckeditor_wiris/integration/showimage.php?formula=f12db7e19aaee04c69b87dac5b44ae11.png\")
.
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Input voltage is
![\"\"](\"/test/fckeditor/editor/plugins/fckeditor_wiris/integration/showimage.php?formula=e49c5f860c43719745ddb9e1714cc632.png\")
.
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Output voltage is
![\"\"](\"/test/fckeditor/editor/plugins/fckeditor_wiris/integration/showimage.php?formula=4ba6589db49cbe875ef9f90e92b8b264.png\")
.
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Relation between
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,
![\"\"](\"/test/fckeditor/editor/plugins/fckeditor_wiris/integration/showimage.php?formula=93c28504c08cf7a629e1c4a45477fa2f.png\")
and
![\"\"](\"/test/fckeditor/editor/plugins/fckeditor_wiris/integration/showimage.php?formula=6892eb2d3f0be814dcae2f11e4c23c7d.png\")
is
![\"\"](\"/test/fckeditor/editor/plugins/fckeditor_wiris/integration/showimage.php?formula=112e516416a47ee7952df00da23aabc0.png\")
.
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Step 2:
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Formula for is ![\"\"](\"/test/fckeditor/editor/plugins/fckeditor_wiris/integration/showimage.php?formula=c2b1d7d27fd5bdceaa6f1affed022c89.png\")
.
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![\"\"](\"/test/fckeditor/editor/plugins/fckeditor_wiris/integration/showimage.php?formula=8a6f374a0d146ba2d81e2d4fb99565fd.png\")
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Formula for is ![\"\"](\"/test/fckeditor/editor/plugins/fckeditor_wiris/integration/showimage.php?formula=2003094883c6470dbd7ecf8191e735e0.png\")
.
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![\"\"](\"/test/fckeditor/editor/plugins/fckeditor_wiris/integration/showimage.php?formula=d578e5682c8d18827a0510cce5b71962.png\")
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Therefore the values are ![\"\"](\"/test/fckeditor/editor/plugins/fckeditor_wiris/integration/showimage.php?formula=b8fcb789bf89d3201cdbf125a4151045.png\")
and ![\"\"](\"/test/fckeditor/editor/plugins/fckeditor_wiris/integration/showimage.php?formula=7a7e419157da804a80949ce3a70e3e1e.png\")
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A common base amplifier produces an output current change of 4 mA with an input current of 2 µA. The output voltage changes with 6 V by means of 2 V input voltage.
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Calculate the following:
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4.3.1 hib
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4.3.2 hrb
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Step 1:
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The input current is 2 µA.
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The output current is 4 mA.
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The input voltage is 2 V.
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The output voltage is 6 V.
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Find ou
and
in common base configuration.
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Draw the common base configuration.
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Observe the figure.
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Input current is
.
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Output current is
.
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Input voltage is
.
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Output voltage is
.
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Formula for is ![\"\"](\"/test/fckeditor/editor/plugins/fckeditor_wiris/integration/showimage.php?formula=2cac9487a2c3174954f421429b39d3fb.png\")
.
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![\"\"](\"/test/fckeditor/editor/plugins/fckeditor_wiris/integration/showimage.php?formula=630da66a96f166498ef4765571f10981.png\")
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Formula for is .
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Therefore the values are ![\"\"](\"/test/fckeditor/editor/plugins/fckeditor_wiris/integration/showimage.php?formula=429295b580f8e84b6a507b4835589426.png\")
and .
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![\"\"](\"/userfiles/tran2.gif\")
![\"\"](\"/test/fckeditor/editor/plugins/fckeditor_wiris/integration/showimage.php?formula=cc019aa6f47a84753359ca471a747071.png\")