between block and slab:
\ms = 0.80 mk = 0.50
\between slab and floor:
\ms = 0.15 mk = 0.10
\A 30-kg slab rests on the floor. A 10-kg block rests on top of the slab. The coefficients of friction between the various surfaces are shown to the right of the figure. The block is pulled by a horizontal force F = 75 N.
\9) What is the acceleration of the 30-kg slab? Show your work!
\Mass of the slab is 30 kg.
\Mass of the block is 10 kg.
\Coefficient of kinetic friction between slab and floor is 0.10.
\Draw the free body diagram for the above situation :
\Forces acting on the 10 kg block is .
Forces acting on the 30 kg block is .
Formula for the acceleration of the slab is .
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CONTD>>>>>>>>>
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A car of mass 1100 kg is being pulled by the a tow truck.
\Normal Force of 1200 N.
\A frictional force pulls the car towards south.
\Starting from rest, the car accelerates and moves 60 mts in 25 seconds.
\The force acting on the car are shown below :
\Total force acting on the car : .
Frictional force : .
Find acceleration.
\Equation of Motion : .
Initial velocity is zero.
\Distance travelled by the car is 60 mts.
\Time taken by the car is 25 seconds.
\ m/sec².
Frictional force :
\Solution:
\Frictional force