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between block and slab: 

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ms = 0.80    mk = 0.50

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between slab and floor: 

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ms = 0.15    mk = 0.10

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A 30-kg slab rests on the floor.  A 10-kg block rests on top of the slab.  The coefficients of friction between the various surfaces are shown to the right of the figure.  The block is pulled by a horizontal force F = 75 N.

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9)         What is the acceleration of the 30-kg slab?  Show your work!

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Mass of the slab is 30 kg.

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Mass of the block is 10 kg.

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Coefficient of kinetic friction between slab and floor is 0.10.

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Draw the free body diagram for the above situation :

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\"\"

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Forces acting on the 10 kg block is \"\".

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Forces acting on the 30 kg block is \"\".

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Formula for the acceleration of the slab is \"\".

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\"\"

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\"\"

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CONTD>>>>>>>>>

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A car of mass 1100 kg is being pulled by the a tow truck.

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Normal Force of 1200 N.

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A frictional force pulls the car towards south.

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Starting from rest, the car accelerates and moves 60 mts in 25 seconds.

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The force acting on the car are shown below :

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\"\"

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Total force acting on the car : \"\".

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\"\"

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\"\"

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Frictional force : \"\".

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Find acceleration.

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Equation of Motion : \"\".

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Initial velocity is zero.

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Distance travelled by the car is 60 mts.

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Time taken by the car is 25 seconds.

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\"\"

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\"\" m/sec².

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Frictional force :

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\"\"

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\"\"

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Solution:

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Frictional force \"\"