Step 1:
\The series is .
The Comparison Test :
\Suppose that and
are series with positive terms.
(i) If is convergent and
for all n , then
is also convergent.
(ii) If is divergent and
for all n, then
is also divergent.
\
The dominant part of the numerator is 1 and the dominant part of the denominator is .
Now compare the given series with the series .
Observe that .
Step 2 :
\The obtained series is .
Definition of p - series :
\The p - series is convergent if
and divergent if
.
Here p = 1.
\Hence the series is divergent.
Here and
is divegent.
By comparison test, also diverges.
Step 3:
\\
Solution :
\ is divergent.
\
\
\
\
\
\
Step 1:
\The series is .
The Comparison Test :
\Suppose that and
are series with positive terms.
(i) If is convergent and
for all n , then
is also convergent.
(ii) If is divergent and
for all n, then
is also divergent.
\
The dominant part of the numerator is 1 and the dominant part of the denominator is .
Now compare the given series with the series .
Observe that .
Step 2 :
\The obtained series is .
Definition of p - series :
\The p - series is convergent if
and divergent if
.
Here p = 1.
\Hence the series is divergent.
Here and
is divegent.
By comparison test, also diverges.
Solution :
\ is divergent.
\
\
\
\
Step 1:
\\
The series is .
Integral test :
\Suppose is continuous , positive and decreasing on the interval
then
(i) is convergent the
is also convergent.
(i) is divergent the
is also divergent.
The function is continuous , positive and decreasing on the interval
.
The series is divergent.
\Solution:
\The series is divergent.