Step 1:

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The series is \"\".

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The Comparison Test :

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Suppose that \"\"and \"\" are series with positive terms.

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(i) If \"\" is convergent and \"\" for all n , then \"\" is also convergent.

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(ii) If \"\" is divergent and \"\" for all n, then \"\" is also divergent.

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The dominant part of the numerator is 1 and the dominant part of the denominator is \"\".

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Now compare the given series with the series \"\".

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Observe that \"\". 

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Step 2 :

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The obtained series is \"\".

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Definition of p - series :

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The p - series \"\" is convergent if \"\"and divergent if \"\".

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Here p = 1.

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Hence the series \"\" is divergent.

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Here \"\" and \"\" is divegent.

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By comparison test, \"\" also diverges.

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Step 3:

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Solution :

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\"\" is divergent.

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Step 1:

\

The series is \"\".

\

The Comparison Test :

\

Suppose that \"\"and \"\" are series with positive terms.

\

(i) If \"\" is convergent and \"\" for all n , then \"\" is also convergent.

\

(ii) If \"\" is divergent and \"\" for all n, then \"\" is also divergent.

\

 

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The dominant part of the numerator is 1 and the dominant part of the denominator is \"\".

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Now compare the given series with the series \"\".

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Observe that \"\".

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Step 2 :

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The obtained series is \"\".

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Definition of p - series :

\

The p - series \"\" is convergent if \"\"and divergent if \"\".

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Here p = 1.

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Hence the series \"\" is divergent.

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Here \"\" and \"\" is divegent.

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By comparison test, \"\" also diverges.

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Solution :

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\"\" is divergent.

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Step 1:

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The series is \"\".

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Integral test :

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Suppose \"\" is continuous , positive and decreasing on the interval \"\" then

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(i) \"\" is convergent the \"\" is also convergent.

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(i) \"\" is divergent the \"\" is also divergent.

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The function \"\" is continuous , positive and decreasing on the interval \"\".

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\"\"

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\"\"

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\"\"

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The series is divergent.

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Solution:

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The series is divergent.