\
(1)
\\
(1)
\Step 1:
\Redraw the circuit showing branch currents.
\Apply KVL for the first loop.
\Apply KVL for the second loop.
\Substitute in equation (1).
Since the current is in opposite direction to the assumed current direction, .
Solution:
\The branch current is .
\
\
(2)
\Step 1:
\Observe the circuit.
\Apply KVL for the first loop.
\The branch current is . (from (1))
The branch current is .
Solution:
\The branch current is .
\
(3)
\Step 1:
\Observe the circuit.
\The branch currents are and
.
The current flowing through the resistor is
.
The branch current is .
Solution :
\The branch current is .