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$\"\"$

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(1)

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Step 1:

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Find the Thevinins equivalent resistance.

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1.Open the load resistor.

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2.Open Current Sources and Short Voltage Sources.

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3.Calculate the Open Circuit Resistance. The resultant open circuit resistance is the thevenin Resistance (R_TH).

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Redraw the circuit :

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$\"\"$

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The Resistance $\"\"$ and $\"\"$ are in series.

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$\"\"$

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$\"\"$

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The resistance $\"\"$ is in parallel to $\"\"$ .

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Equivalent reistance is $\"\"$ .

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$\"\"$

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Thevinins equivalent resistance is $\"\"$ .

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Solution :

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Thevinins equivalent resistance is $\"\"$ .

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(2)

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Step 1:

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Find the thevinins equivalent voltage.

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1.Open the load resistor.

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2.Calculate the Open Circuit Voltage. This is the Thevenin Voltage (V_TH).

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Use Superposition principle to calculate volatge across A and B.

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Find the current through 10 $\"\"$ resistor.

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Super Position Theorem :

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Take one voltage source at a time and replace all other with short or internal resistance.

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$\"\"$

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Current in the circuit is $\"\"$ .

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$\"\"$

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Current in the circuit is $\"\"$ .

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Voltage drop acoss 10 $\"\"$ resistor : $\"\"$ .

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$\"\"$

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$\"\"$ .

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Step 2:

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Take one voltage source at a time and replace all other with short or internal resistance.

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$\"\"$

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Current in the circuit is $\"\"$ .

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$\"\"$

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Current in the circuit is $\"\"$ .

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Voltage drop acoss 10 $\"\"$ resistor : $\"\"$ .

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$\"\"$

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$\"\"$ .

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Step 3:

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Now observe the circuit.

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The Voltage acoss the terminal A and B is $\"\"$ .

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$\"\"$

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Thevinins equivalent voltage is $\"\"$ .

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Solution :

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Thevinins equivalent voltage is $\"\"$ .