Step 1:

\

The equation is \"\".

\

Domain :

\

The domain of a  function is the set of values of \"\" for which the function is mathematically correct.

\

The function  under the square root should not be negative.

\

\"\".

\

Solve the inequality \"\".

\

\"\"

\

\"\" is always greater than zero, hence \"\".

\

\"\"

\

\"\".

\

Therefore, the domain of the function is \"\".

\

The range of the function is \"\".

\

Step 2:

\

Find the \"\"- intercept, by equating \"\".

\

\"\"

\

\"\" or \"\".

\

\"\" or \"\"

\

\"\" or \"\"

\

\"\" or \"\"

\

\"\" is not in the domian of the function .

\

Therefore,the \"\"- intercepts are  \"\".

\

Step 3:

\

Find \"\"- intercept , by substitute \"\" in \"\".

\

\"\"

\

\"\"

\

\"\"

\

\"\".

\

\"\" is the not in the range of the function.

\

Therefore the \"\"- intercept is \"\".

\

Solution :

\

The \"\"-intercepts are \"\" and \"\"- intercept is \"\".

\

 

\

 

\