Step 1:
\Mass of the bullet m is 22 g=0.022 kg.
\Initial velocity of the bullet is 290 m/s .
\Final velocity of the bullet is 140 m/s .
\Mass of the tagret M is 2 kg.
\Change in velocity is m/s.
Conservation of momentum:
\In a collision, the momentum change of object 1 is equal to and opposite of the momentum change of object 2.
\So momentum change of bullet.
Momentum change in target.
Conservation of momentum
\
Change in velocity of target = 1.65 m/s .
\The target is initially at rest so Vi = 0 .
\Change in velocity of target = Vf - Vi = 1.65 m/s
\Vf - 0 = 1.65 m/s
\Vf = 1.65 m/s
\So the targets speed just after the bullet emerges is 1.65 m/s .