(1)
\Step 1 :
\Second partials test :
\ If f have continuous partial derivatives on an open region containing a point for which
and
.
To test for relative extrema of f , consider the quantity
\1. If and
, then f has a relative minimum at
.
2. If and
, then f has a relative maximum at
.
3. If and
, then
is a saddle point.
4. The test is inconclusive if .
Step 2 :
\ The function is .
Apply partial derivative on each side with respect to x.
\Differentiate partially with respect to x.
Differentiate partially with respect to y.
Step 3 :
\The function is .
Apply partial derivative on each side with respect to y.
\Differentiate partially with respect to y.
Differentiate partially with respect to x.
Step 4 :
\Find the critical points.
\Equate to zero.
Equate to zero.
Substitute in the above equation.
Substitute in
.
The critical point is .
Step 5 :
\Find the quantity of d .
\Find at
.
If and
, then f has a relative minimum at
.
Relative maximum at .
Solution :
\Relative maximum at .
\
\
\
\
\
\
\
(2)
\Step 1 :
\Second partial test :
\ If f have continuous partial derivatives on an open region containing a point for which
and
.
To test for relative extrema of f , consider the quantity
\1. If and
, then f has a relative minimum at
.
2. If and
, then f has a relative maximum at
.
3. If then
is a saddle point.
4. The test is inconclusive if .
Step 2 :
\ The function is .
Apply partial derivative on each side with respect to x.
\Differentiate partially with respect to x.
Differentiate partially with respect to y.
Step 3 :
\The function is .
Apply partial derivative on each side with respect to y.
\Differentiate partially with respect to y.
Differentiate partially with respect to x.
Step 4 :
\Find the critical points.
\Equate to zero.
Equate to zero.
The critical point are and
.
Step 5 :
\Find the quantity of d .
\Case(i): Consider critical point as .
As , then f has a saddle point at
.
Case(ii): Consider critical point as .
Find at
.
If and
, then f has a relative maximum at
.
Relative maximum at .
Case(iii): Consider critical point as .
Find at
.
If and
, then f has a relative minimum at
.
Relative minimum at .
Case(iv): Consider critical point as .
As , then f has a saddle point at
.
Solution :
\Relative maximum at .
Relative minimum at .
Saddle points are and
.