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.Step 1:
\ \If a particle undergoes SHM with amplitude 0.16 m what is the total distance it travels in one period?
\The Particle undergoes simple harmonic motion.
\The amplitude of the particle in simple harmonic motion is is .
In one period the particle will travel from one extreme position to the other (a distance of 2A) and backagain.
\The total distance traveled is ![\"\"](\"/test/fckeditor/editor/plugins/fckeditor_wiris/integration/showimage.php?formula=6f5304b077bc60d33f0c82ee25579e09.png\")
.
Substitute .
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.
The total distance travelled in one period is ![\"\"](\"/test/fckeditor/editor/plugins/fckeditor_wiris/integration/showimage.php?formula=1d3ce7dcb3798ceac01c514641707929.png\")
.
In one period it goes from zero amplitude to maximum amplitude, back again to zero, the other direction to maximum amplitude and back to zero again.
\That\\'s where the 4 comes from.
\The particle would travel 4 times the amplitude, so the distance = 4x0.18 = 0.72 m
\In one period the particle will travel from one extreme position to the other (a distance of 2A) and backagain. The total distance traveled is
\\ \ what is the total distance it travels in one period?If a particle undergoes SHM with amplitude 0.16 m what is the total distance it travels in one period?