A pendulum has a peroid of 0.80 s on Earth. What is its period on Mars, where the acceleration of gravity is about 0.37 that on Earth. \ \ \ \ I used Formula T=2pi(sq root of L/g). \ \ \ \ 80=6.28 (sq root of L/9.8) \ \ \ \ (80/6.28) ^2 = L/9.8 \ \ \ \ 162= L/9.8 \ \ \ \ L=1590 \ \ \ \ On Mars .37 x 9.8 = 3.62 m/s^2 \ \ \ \ T=6.28(sq root of 1590/3.62) \ \ \ \ T=6.28(21) \ \ \ \ T= 131s The book says the answer is 1.3s. I think the book is \ \ \ \ right, but I can\\'t figure out where I am messing up at. \ \ \ \ Thanks Tim

A pendulum has a period of 1.94 s on Earth \ \ \ \ What is its period on Mars, where the acceleration of gravity is about 0.37 that on Earth?

The pendulum has time period is $\"\"$ .

Find the length of the pendulum.

The time period of the simple pendulum is $\"image\"$ , where $\"image\"$ is the length of the pendulum and $\"image\"$ is acceleration due to gravity.