A cord of mass 0.55kg is stretched between two supports 30 m apart. If the tension in the cord is 150N, how long will it take a pulse to travel from one support to the other?

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Now we will apply a special formula from the text book, which is: v = (Ft/(m/l))^{1/2 \ \}or v = ÖT/µ^{\ \}Where µ = mass/length for the cord, and T is the tension in the cord. \ \ have: T = 150N; m = 0.55kg; and l = 30m, so µ = (.55 kg)/(30 m) = 0.01833 kg/m \ \ Therefore, v = ÖT/µ = Ö(150 N/(0.01833 kg/m)) = 90.45m/s \ \ The time will be: t = s/v = (30 m)/(90.45 m/s) = 0.33s \ \
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Tension T = 154 N \ \ Mass per unit length of the cord, m= mass / length = 0.5 / 26 = 0.019 kg/m \ \ \ \ Now \ \ velocity of wave in the string is given by \ \ v = sqrt.(T/m) = 44.74 m/s \ \ \ \ Time = 26 / 44.74 = 0.58 s
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A cord of mass 0.65 kg is stretched between two supports 7.2 m apart. \ \ \ \ If the tension in the cord is 110 N , how long will it take a pulse to travel from one support to the other?

The mass of the cord is $\"\"$ .