Two children are sending signals along a cord of total mass 0.56 kg tied between tin cans with a tension of 39 N . It takes the vibrations in the string 0.60 s to go from one child to the other. \ \ \ \ How far apart are the children?

The speed c of the elastic wave is : \ \ c = sqr(T/μ) T = 31 N ; μ = m/L is the linear density. Then \ \ c = sqr(T*L/m). \ \ Δx = L = c*t --> L^2 = (T*L/m)*t^2 \ \ Δx = (T/m)*t^2 = 12.8 m

The mass of the cord is .

The tension in the cord is .

Time taken for vibration of string is 0.60 sec.

The velocity of the transverse wave on the cord is , where is the tension in the cord and .

Velocity of the wave , where and is the time.

Substitute and

Distance between childrens is 41.78 m.