\
\
Step 1:
\Use Superposition principle to calculate volatge across A and B.
\Super Position Theorem :
\Take one current source at a time and replace all other with voltage with short or internal resistance and current sources with open.
\The current flowing in the circuit is .
in polar form can be written as
.
in complex form can be written as
.
Apply current divider rule: .
Find the total impdenace .
is in series with
.
is in series with
.
is in parallel to
is in series with
,
and
Current divider rule:
\
Find the voltage drop across the impedance .
\
V.
Step 2:
\Take one voltage source at a time and eplace all other with voltage with short or internal resistance and current sources with open.
\The voltage in the circuit is
in polar form can be written as
.
in complex form can be written as
.
\
Apply KVL to loop 1:
\ Find the voltage drop across the impedance .
\
V.
Step 3:
\By superposition principle :
\The Voltage acoss the resistor is
.
Voltage acoss the resistor is
Solution:
\Voltage acoss the resistor is