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\"\"
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Step 1:

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Draw the related diagram:

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\"\"

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The angle of the field at the dot from the upper left charge \"\" is \"\".

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The angle of the field at the dot from the lower left charge \"\" is \"\".

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The angle of the field at the dot from the lower right charge \"\" is \"\".

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Electric field due to charged particle is \"\", where \"\".

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\"image\" is the permittivity of free space \"image\".

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\"\" is the charge of the electron.

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\"\" is the distance between the two point charges.

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Step 2:

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The distance between the upper left charge and the point \"\" is \"\".

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For the charged particle along upper left surface is \"\".

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The distance between the lower left charge and the point \"\" is \"\".

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For the charged particle along lower left surface is \"\".

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The distance between the lower right charge and the point \"\" is \"\".

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For the charged particle along lower right surface is \"\".

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Step 3:

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Find the net electric field.

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\"\" is sum of horizontal and vertical components.

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Find the sum of horizontal components.

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\"\"

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\"\".

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Substitute \"\" and \"\".

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\"\"

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\"\"

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\"\".

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The horizontal component is \"\".

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Find the sum of vertical components.

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\"\"

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\"\".

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Substitute \"\" and \"\".

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\"\"

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\"\"

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\"\".

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The vertical component is \"\".

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\"\".

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\"\".

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The electric field at point \"\" in component form is \"\".

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Therefore \"\".

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Find the magnitude of electric field strength.

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\"\"

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Strength of the electric field is \"\"

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Find the direction of electric field.

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\"\"

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\"\"

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Direction of electric field is \"\" above the \"\"-axis.

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Solution:

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Strength of the electric field is \"\"

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Direction of electric field is \"\" above the \"\"-axis.

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