\
Step 1:
\Draw the related diagram:
\The angle of the field at the dot from the upper left charge is
.
The angle of the field at the dot from the lower left charge is
.
The angle of the field at the dot from the lower right charge is
.
Electric field due to charged particle is , where
.
is the permittivity of free space
.
is the charge of the electron.
is the distance between the two point charges.
Step 2:
\The distance between the upper left charge and the point is
.
For the charged particle along upper left surface is .
The distance between the lower left charge and the point is
.
For the charged particle along lower left surface is .
The distance between the lower right charge and the point is
.
For the charged particle along lower right surface is .
Step 3:
\Find the net electric field.
\ is sum of horizontal and vertical components.
Find the sum of horizontal components.
\.
Substitute and
.
.
The horizontal component is .
Find the sum of vertical components.
\.
Substitute and
.
.
The vertical component is .
.
.
The electric field at point in component form is
.
Therefore .
Find the magnitude of electric field strength.
\Strength of the electric field is
Find the direction of electric field.
\Direction of electric field is above the
-axis.
Solution:
\Strength of the electric field is
Direction of electric field is above the
-axis.
\
\