The system of equations are .
Use the elimination method to make a system of two equations in two variables.
\To get two equations 1 and 2 that contain opposite coefficient of z - variable multiply the first equation by 4.
\Write the equations 1 and 2 in column form and add the corresponding columns to eliminate z - variable.
\The resultant equation is taken as fourth equation : 7x - 11y = 65.
\To get two equations 2 and 3 that contain opposite coefficient of z - variable multiply the third equation by 2.
\Write the equations 2 and 3 in column form and add the corresponding columns to eliminate z - variable.
\The resultant equation is taken as fifth equation : - 5x - 7y = 13.
\Solve the system of two equations with two variables.
\To get two equations 4 and 5 that contain opposite coefficient of x - variable multiply the fourth equation by 5 and multiply the fifth equation by 7.
\Write the equations 4 and 5 in column form and add the corresponding columns to eliminate x - variable.
\The resultant equation - 104y = 416 ------> y = - 4.
\Use one of the equation with two variables (Equation: 4 or 5) to solve for x.
\The fourth equation: 7x - 11y = 65.
\7x - 11(- 4) = 65
\7x + 44 = 65
\7x = 21
\x = 3.
\Solve for z using one of the original equations with three variables.
\The first equation: x - 3y + z = 13.
\(3) - 3(- 4) + z = 13
\3 + 12 + z = 13
\15 + z = 13
\z = - 2.
\The solution (x, y, z) = (3, - 4, - 2).