Write the expression in long division form [ p(x) = x2 + 6x + 3 ] / [ s(x) = x + 3 ].
\Divide the first term of the dividend [ p(x) ] by the first term of the divisor [ s(x) ] : x2/x = x.
\So,the first term of the quotient [ q(x) ] is x. Multiply (x + 3) by x and subtract.
\Divide the first term of the last row by first term of the divisor : 3x/x = 3.
\So,the second term of the quotient is 3. Multiply (x + 3) by 3 and subtract.
\The remainder is the last entry in the last row.There fore, r = 5.
\The number along the bottom row are the coefficients of the quotient.
\The result of the division is
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The solution q(x) = x + 3 and r = 5.
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