The function is \"\".

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Apply first derivative with respect to x.

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\"\"

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\"\"

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Apply second derivative with respect to x.

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\"\"

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\"\"

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\"\"

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\"\"

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\"\"

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\"\"

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To find the critical numbers \"\" or \"\" does not exist.

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Find the critical numbers \"\".

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\"\"

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\"\"

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Find the critical numbers, \"\" does not exist that means denominator not equals to zero..

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Completing the square Method :

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The denominator is (x2 + 6x + 11)2 = 0.

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x2 + 6x + 11 = 0

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Separate variables and constants aside by subtracting 11 from each side.

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x2 + 6x = - 11

\ To change the expression into a perfect square trinomial add (half the x coefficient)² to each side of the expression. \

Here x coefficient = 6. So, (half the x coefficient)2 = (6/2)2= 9.

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Add 9 to each side.

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x2 + 6x + 9 = - 11 + 9

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x2 + 2(x)(3) + 32 = - 2

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Apply Perfect Square Trinomial : u2 + 2uv + v2 = (u + v)2.

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(x + 3)2 = (i√2)2                                    [ i2 = - 1]

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x + 3 = ± i√2

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x = - 3 ± i√2.

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The above imaginary numbers are not a critical numbers.

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The critical number of the function is x = - 3.

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If f " (c) > 0 (positive) ------> minimum point.

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If f " (c) < 0 (negative) ------> maximum point.

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\"\"

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To find the maximum point substitute \"\" in the original function.

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\"\"

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