The system of equations are (3/4)x + (4/5)y = 5/2 and (1/2)x - (9/10)y = - 11/2.
\Equation 1 : (3/4)x + (4/5)y = 5/2 ⇒ 0.75x + 0.8y = 2.5.
\Equation 2 : (1/2)x - (9/10)y = - 11/2 ⇒ 0.5x - 0.9y = - 5.5.
\Neither variable has a common coefficient.The coefficient of the y - variables are 0.8 and 0.9 and their least common multiple is 0.72, so multiply each equation by the value that will make the y - coefficient 0.72.
\To get two equations that contain opposite terms multiply the first equation by 0.9 and multiply the second equation by 0.8.
\Write the equations in column form and add the corresponding columns to eliminate y - variable.
\The resultant equation is 1.075x = - 2.15 ⇒ x = - 2.
\Substitute the value of x = - 2 in either of the original equations and solve for y.
\The second equation : 0.5x - 0.9y = - 5.5.
\0.5(- 2) - 0.9y = - 5.5
\- 1 - 0.9y = - 5.5
\- 0.9y = - 4.5
\y = 5.
\The solution (x, y) = (-2, 5).
\