In any triangle, two of the interior angles are always acute (less than 90 degrees)*, so there are three possibilities for the third angle:

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The oblique triangle means a triangle that contains no right angle.

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Therefore that triangle is either acute triangle or obtuse triangle.

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The formula for the area of oblique triangle is Area = 1/2 bc sin A = 1/2 ab sin C = 1/2 ac sin B.

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if angle A is 90o, the formula gives the area for a right triangle :

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Area = 1/2 bc sin A = 1/2 bc sin 90o = 1/2 bc = 1/2 (base)(height).

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The base of the triangle is 8 units and height is 3 units and its area is 12 square units.

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To check  the above triangle is right angle triangle, as follows :

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Area = 1/2 (base)(height).

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12 = 1/2 (8)(3)

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12 = 24/2

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12 = 12.

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The above statement is true, so the given triangle is right angle triangle.

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To tell  the above triangle is right angle triangle, by use another method as follows :

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Let the sides of the triangle are a = 8 units, b = 3 units and c.

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Here to find the remaining side by use the Pythagorean Theorem, (hypotenuse)2 = (opposite)2 + (adjacent)2

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c = √[ (3)2 + (8)2 ] = √[ 9 + 64 ] = √(73).

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a = 8, b = 3 and c = √(73) ≅ 8.544.

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a2 = 64, b2 = 9 and c2 = 73.

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The formula for the area of oblique triangle is Area = 1/2 bc sin A = 1/2 ab sin C = 1/2 ac sin B

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Find angle A:

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Area = 1/2 bc sin A

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12 = (1/2) (3)(8.544) sin A

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24 = (3)(8.544)sin A

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8/(8.544) = sin A

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0.936 = sin A

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A ≅ 69.444

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Find angle B:

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Area = 1/2 ac sin B

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12 = (1/2) (8)(8.544) sin B

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3 = (8.544)sin B

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3/(8.544) = sin B

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0.351 = sin B

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B ≅ 20.556.

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The remaining angle is C = 180o - (69.444o + 20.556o) = 180o - 90o = 90o.

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The given triangle is right angle triangle.