In any triangle, two of the interior angles are always acute (less than 90 degrees)*, so there are three possibilities for the third angle:
\The oblique triangle means a triangle that contains no right angle.
\Therefore that triangle is either acute triangle or obtuse triangle.
\The formula for the area of oblique triangle is Area = 1/2 bc sin A = 1/2 ab sin C = 1/2 ac sin B.
\if angle A is 90o, the formula gives the area for a right triangle :
\Area = 1/2 bc sin A = 1/2 bc sin 90o = 1/2 bc = 1/2 (base)(height).
\The base of the triangle is 8 units and height is 3 units and its area is 12 square units.
\To check the above triangle is right angle triangle, as follows :
\Area = 1/2 (base)(height).
\12 = 1/2 (8)(3)
\12 = 24/2
\12 = 12.
\The above statement is true, so the given triangle is right angle triangle.
\To tell the above triangle is right angle triangle, by use another method as follows :
\Let the sides of the triangle are a = 8 units, b = 3 units and c.
\Here to find the remaining side by use the Pythagorean Theorem, (hypotenuse)2 = (opposite)2 + (adjacent)2
\c = √[ (3)2 + (8)2 ] = √[ 9 + 64 ] = √(73).
\a = 8, b = 3 and c = √(73) ≅ 8.544.
\a2 = 64, b2 = 9 and c2 = 73.
\The formula for the area of oblique triangle is Area = 1/2 bc sin A = 1/2 ab sin C = 1/2 ac sin B
\Find angle A:
\Area = 1/2 bc sin A
\12 = (1/2) (3)(8.544) sin A
\24 = (3)(8.544)sin A
\8/(8.544) = sin A
\0.936 = sin A
\A ≅ 69.444
\Find angle B:
\Area = 1/2 ac sin B
\12 = (1/2) (8)(8.544) sin B
\3 = (8.544)sin B
\3/(8.544) = sin B
\0.351 = sin B
\B ≅ 20.556.
\The remaining angle is C = 180o - (69.444o + 20.556o) = 180o - 90o = 90o.
\The given triangle is right angle triangle.