![\"\"](\"http://www.mathskey.com/test/fckeditor/editor/plugins/fckeditor_wiris/integration/showimage.php?formula=a2a25ecf50aa690540e6109f08819c5d.png\")
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The square length is s.
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Let the vertices of square A (0,0), B(0,s), C(s,0) and D(s,s).
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(0,0) is origin.
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(0,s) is on y axis at "s".
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(s,0) is on x - axis at " s".
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(s,s) is in first quadrant.
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The end points of the diagonals (non - adjacent pairs) are (0,0) (s,s) and second pair is (0,s)(s,0).
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Find the mid point of diagonals .
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Mid point of AD
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![\"\"](\"http://www.mathskey.com/test/fckeditor/editor/plugins/fckeditor_wiris/integration/showimage.php?formula=0242d55698c70a6a5a10357ddf8d453d.png\")
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![\"\"](\"http://www.mathskey.com/test/fckeditor/editor/plugins/fckeditor_wiris/integration/showimage.php?formula=f5becd828c333963f77c89dc32d51073.png\")
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![\"\"](\"http://www.mathskey.com/test/fckeditor/editor/plugins/fckeditor_wiris/integration/showimage.php?formula=1d73f66c565f7917235d825482b18564.png\")
![\"\"](\"http://www.mathskey.com/test/fckeditor/editor/plugins/fckeditor_wiris/integration/showimage.php?formula=b1e552e67f01af9bd595859f4d08ef3a.png\")
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Mid point of BC
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![\"\"](\"http://www.mathskey.com/test/fckeditor/editor/plugins/fckeditor_wiris/integration/showimage.php?formula=4a48418e2516d02faf7fa0c3cf21c879.png\")
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![\"\"](\"http://www.mathskey.com/test/fckeditor/editor/plugins/fckeditor_wiris/integration/showimage.php?formula=3b64e3a4d19a0130bebb52eea4d0ff94.png\")
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![\"\"](\"http://www.mathskey.com/test/fckeditor/editor/plugins/fckeditor_wiris/integration/showimage.php?formula=e2d0196f1aeb29ec8987ec553fcdf707.png\")
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From the graph the diagonals of a square intersect their mid points.