The function is  \"\".

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The above function is in the form \"\".

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Here A is amplitude, B is stretch along x-axis, d is a constant determines the vertical shift.

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The amplitude of the function is \"\".

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1)

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The period of a sine function is given by \"\".

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In the given function B is 2.

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So, the period is \"\".

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2)

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Phase shift of a function is given by \"\".

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In the given function c is \"\".

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Phase shift is \"\".

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3)

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In the given function d is zero, that means there is no vertical shift in the function.

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4)

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To find the asymptotes of the function, graph the function over a period.

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The solutions of the given functions are

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\"\"

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\"\".

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Taking \"\"as an interval difference plot the graph. \ \

\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \
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\"\"
\"\" \

\"\" \ \

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\"\"

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\"\" \ \

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\"\"

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\"\"

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\"\"

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\"\"

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\"\"

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\"\"

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  Now plot these points

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\"pro

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Since sine function is a continues sinusoidal function.

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So, it has no vertical asymptotes.

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And horizontally it is oscillating between \"\", but it is not converging at either \"\".

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So, it also doesn\\'t have horizontal asypmtotes.

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5)

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From the graph we can also say the domain and range of the function.

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Domain is \"\".

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It is oscillating between \"\", so the range is \"\".