The equation is .
To find the equation of the axis of symmetry.
\The equation is compared to , then a = 1, b = 4 and c = – 9.
The equation for the axis of symmetry of a parabola: .
(Substitute a = 1, and b = 4)
(Simplify)
The equation of the axis of symmetry is .
To find the coordinates of the vertex.
\Since the equation of the axis of symmetry is .
The vertex lies on the axis, the x-coordinate for the vertex is –2.
\ (Substitute
)
(Simplify)
(Subtract:
)
Then the vertex is at (–2, –11).
To Identify the vertex as a maximum or minimum.
\Since the coefficient of the term is positive.
The parabola opens upward and the vertex is a minimum point.
\The equation of the axis of symmetry is and symmetry choose x = 2.
To find the y-coordinate that satisfies the equation .
(Substitute x = 2)
(Simplify)
(Subtract:
)
The coordinate point is (2, 3).
Since the graph is symmetrical about its axis of symmetry , and find another point on the other side of the axis of symmetry.
The point at (2, 3) is 4 units to the right of the axis.
\Go 4 units to the left of the axis and plot the point (–6, 3).
\Repeat this for several other points. Then sketch the parabola.
To graph of the function .
Use these ordered pairs to graph the equation.
\1. Use the symmetry of the parabola to upward the graph.
\2. Draw a coordinate plane.
\3. graph the vertex and the axis of symmetry.
\4. Plot the points.
\5. Draw a line through these points.
\To graph of the function .
The solution of graph.
\