$\"\"$

From the given data : P = $1000, r = 6% and t = 40 years.

r = $\"\"$ .

Formula for n compoundings per year: $\"\"$ . $\"\"$

For 1 compounding per 40 years, the balance is :

$\"\"$ .

For 2 compounding per 40 years, the balance is :

$\"\"$ .

For 4 compounding per 40 years, the balance is :

$\"\"$ .

For 12 compounding per 40 years, the balance is :

$\"\"$ .

For 365 compounding per 40years, the balance is : $\"\"$

$\"\"$ .

Balance for continuous compounding : $\"\"$ .

$\"\"$

The table for compound interest is :

\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \

n	1	\ 2 \	\ 4 \	\ 12 \	365	Continuous
\ A \	\ $10285.71 \	\ $10640.89 \	\ $10828.46 \	\ $10957.45 \	\ $11021 \	$11023.17

$\"\"$

The table for compound interest is :

\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \

n	1	\ 2 \	\ 4 \	\ 12 \	365	Continuous
\ A \	\ $10285.71 \	\ $10640.89 \	\ $10828.46 \	\ $10957.45 \	\ $11021 \	$11023.17