Solve the equations algebraically.
\
From equation (1):
\
From equation (2):
\
Equate the the left hand side of equations (3) and (4).
\
Apply zero product property.
\ and
and
.
Substitute the values in equation (1).
For ,
.
For ,
.
Thus, the intersection points are and
.
Consider .
Compare it to general form .
Discriminant
Since , the equation represents a hyperbola.
Consider .
Compare it to general form .
Since and
have different signs and equal coefficients,
the equation represents a circle.
\Graph the equations:
\
Observe the graph:
\The intersection points are and
.
The intersection points are and
.