The equation is .
This equation is of quadratic type with .
Solve the above equation by the factors method as follows:
\Factor by grouping.
\Partially factor.
\Distributive property.
\Factor completely.
\Set 1 st factor equal to zero.
\.
Set 2 nd factor equal to zero.
\Set 3 rd factor equal to zero.
\.
Thus, the solutions are and
.
Check:
\Substitute the value of in
.
.
The above statement is true. \ \
\\
Substitute the value of in
.
\
.
The above statement is true.
\\ \
\Substitute the value of in
.
.
The above statement is true.
\
The solutions are and
.